/***************************************************************************** * Copyright (c) 2006 Daniel Lerch Hostalot * * Permission is hereby granted, free of charge, to any person obtaining a * copy of this software and associated documentation files (the "Software"), * to deal in the Software without restriction, including without limitation * the rights to use, copy, modify, merge, publish, distribute, sublicense, * and/or sell copies of the Software, and to permit persons to whom the * Software is furnished to do so, subject to the following conditions: * * The above copyright notice and this permission notice shall be included in * all copies or substantial portions of the Software. * * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING * FROM, OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER * DEALINGS IN THE SOFTWARE. ****************************************************************************/ /* Metodo de factorizacion de Fermat ================================= Dado un numero compuesto n determina dos numeros a y b, de manera que n=a·b La idea principal de este metodo consiste en expresar a y b como diferencia de dos cuadrados a=(x+y) b=(x-y) n=a·b=(x+y)(x-y)=x^2-y^2 Compilar con: g++ fermat.cpp -lgmpxx -o fermat */ #include #include int main(int argc, char *argv[]) { using namespace std; mpz_class n, x, u, v, a, b, r; if(argc!=2) { cerr << "Usage: " << argv[0] << " " << endl; return 0; } n = argv[1]; mpz_sqrt(x.get_mpz_t(), n.get_mpz_t()); u = 2*x + 1; v = 1; r = x*x - n; while(r!=0) { if(r>0) { while(r>0) { r -= v; v += 2; } } else { r += u; u += 2; } } a = (u+v-2)/2; b = (u-v)/2; cout << "a: " << a << endl; cout << "b: " << b << endl; return 0; }